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MHT CET202411 May 2024Evening ShiftPhysicsCapacitanceActual

A 1 ~F capacitor is charged to 50 V and is then discharged through 10 mH inductor of negligible resistance. The maximum current in the inductor is

Options

  1. A0.5 A
  2. B1.5 A
  3. C1 A
  4. D0.15 A

Correct answer

A. 0.5 A

Step-by-step solution

Energy stored in capacitor = 1 2 CV ^2 For maximum current energy stored in inductor, 1 2 CV ^2= 1 2 LI ₀^2 . I ₀= Maximum current I ₀^2= CV ^2 ~L = 10⁻⁶ 50 50 10 10⁻³ =25 10⁻² I ₀= 25 10⁻² I ₀=0.5 ~A

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