MHT CET20242 May 2024Evening ShiftPhysicsCapacitanceActual
Charge on a parallel plate capacitor of capacity C is Q, the electric field intensity between its two plates separated by a distance of t is
Options
- AQt C
- BQ Ct
- CC Qt
- DCt Q
Correct answer
B. Q Ct
Step-by-step solution
Electric field intensity between plates of a parallel plate capacitor is E = Q ~A Capacitance of a parallel plate capacitor is aligned & C = A t ~A = Ct & E = Q Ct aligned ...[From(i) and (ii)]