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MHT CET20239 May 2023Morning ShiftPhysicsCapacitanceActual

The potential energy of charged parallel plate capacitor is v₀ . If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

Options

  1. Av₀ K
  2. Bv₀ K^2
  3. Cv₀ K^2
  4. Dv₀ ^2

Correct answer

A. v₀ K

Step-by-step solution

We know, v₀= Q^2 2 C On inserting the slab of dielectric constant k , the new capacitance C ^ = KC New potential energy v₀^ = Q ^2 2 C ^ v₀^1= Q^2 2 KC = v₀ ~K

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