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MHT CET202210 Aug 2022Evening ShiftPhysicsCapacitanceActual

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plate is

Options

  1. AC V^2 2 d
  2. BC^2 V^2 2 d^2
  3. CC^2 V^2 d^2
  4. DV^2 d C

Correct answer

A. C V^2 2 d

Step-by-step solution

Total electric field between the plates of the capacitor. E= V d Then, electric field due to only one plate. E₁= V 2 d force of one plate on another. F=E₁ Q=E₁ C V= V 2 d C V= C V^2 2 d

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