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MHT CET202210 Aug 2022Morning ShiftPhysicsCapacitanceActual

The dielectric slab is introduced between the plates of a parallel plate charged capacitor. Which one of the following quantities will not change?

Options

  1. AThe charge on the capacitor.
  2. BThe potential difference between the plates.
  3. CThe energy stored in the capacitor.
  4. DThe electric field between the plates of a capacitor.

Correct answer

A. The charge on the capacitor.

Step-by-step solution

Only the amount of charge stored in the capacitor will remain constant when the dielectric is inserted between the plates (isolated system). Charge will redistribute, such on the plate Q (1- 1 K ) and Q K on the dielectric interface. The electric field present between the plates of capacitor changes because it varies with the dielectric constant: E^ = Q 4 ₀ K = E K The capacitance increases as: C^ = K ₀ A d =K C The dielectric constant also affects the potential difference as: aligned & Q=C^ V^ =C K V^ =C V & V^ =

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