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MHT CET20228 Aug 2022Morning ShiftPhysicsCapacitanceActual

Two identical parallel plate air capacitors are connected in series to a battery of emf ' V '. If one of the capacitor is inserted in liquid of dielectric constant ' K ' then, potential difference of the other capacitor will become

Options

  1. AK -1 KV
  2. BK +1 KV
  3. C( KV K +1 )
  4. DKV K -1

Correct answer

C. ( KV K +1 )

Step-by-step solution

Let the capacitance of capacitors are C initially. So, afterward C ₁= KC and C ₂= C p.d. across capacitor C ₂ is V ₂= C ₁ ~V C ₁+ C ₂ = KCV C + KC = KV K +1

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