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MHT CET20226 Aug 2022Morning ShiftPhysicsCapacitanceActual

Two condensers C₁ and C₂ in a circuit are joined as shown below. The potential of point A is V₁ and that of B is V₂ . The potential of point D will be

Options

  1. AC₁ V₂+C₂ V₁ C₁+C₂
  2. B1 2 (V₁+V₂ )
  3. CC₂ V₁-C₁ V₂ C₁+C₂
  4. DC₂ (V₁+V₂ ) C₁+C₂

Correct answer

D. C₂ (V₁+V₂ ) C₁+C₂

Step-by-step solution

V₂-V₁ will be divided between C₁ and C₂ . Let V_D be potential at point D. Let Q be the charge on each capacitor. Then the potential drop can be written as: aligned & V₂-V₁=V₂-V_D+V_D-V₁ & V₂-V₁= Q C₂ + Q C₁ & Q= C₁ C₂ (V₂-V₁ ) C₁+C₂ aligned Potential difference across C₁ is V_D=V₁+ C₂ (V₂-V₁ ) C₁+C₂ = C₂ (V₁+V₂ ) C₁+C₂

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