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MHT CET202123 Sep 2021Evening ShiftPhysicsCapacitanceActual

Two parallel plates with dielectric placed between the plates are as shown in figure. The resultant capacity of capacitor will [A = area of plate. t₁, t₂ and t₃ are thickness of dielectric slabs, k₁ , k ₂ and k ₃ are dielectric constant.]

Options

  1. AA ₀ [ t ₁+ t ₂+ t ₃ k ₁+ k ₂+ k ₃ ]
  2. BA ₀ ( k ₁ k ₂ k ₃ ) t ₁ t ₂ t ₃
  3. C~A ₀ [ k ₁ t ₁ + k ₂ t ₂ + k ₃ t ₃ ]
  4. DA ₀ [ t ₁ k ₁ + t ₂ k ₂ + t ₃ k ₃ ]

Correct answer

D. A ₀ [ t ₁ k ₁ + t ₂ k ₂ + t ₃ k ₃ ]

Step-by-step solution

These are three capacitors connected in series. aligned & 1 C = 1 C ₁ + 1 C ₂ + 1 C ₃ = t ₁ ₀ Ak ₁ + t ₂ ₀ Ak ₂ + t ₃ ₀ Ak ₃ & C = A ₀ [ t ₁ k ₁ + t ₂ k ₂ + t ₃ k ₃ ] aligned

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