MHT CET202121 Sep 2021Evening ShiftPhysicsCapacitanceActual
Two identical parallel plate air capacitors are connected in series to a battery of emf ' V '. If one of the capacitor is inserted in liquid of dielectric constant ' K ' then, potential difference of the other capacitor will become
Options
- AK -1 KV
- BK +1 KV
- C( KV K +1 )
- DKV K -1
Correct answer
C. ( KV K +1 )
Step-by-step solution
Let the capacitance of capacitors are C initially. So, afterward C ₁= KC and C ₂= C p.d. across capacitor C ₂ is V ₂= C ₁ ~V C ₁+ C ₂ = KCV C + KC = KV K +1