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MHT CET202121 Sep 2021Evening ShiftPhysicsCapacitanceActual

A condenser of capacity ' C ₁ ' is charged to potential ' V ₁ ' and then disconnected. Uncharged capacitor of capacity ' C ₂ ' is connected in parallel with ' C ₁ '. The resultant potential ' V ₂ ' is

Options

  1. AV ₁ C ₂ C ₁
  2. BC ₂ C ₁+ C ₂
  3. CC ₁ ~V ₁ C ₂
  4. DC ₁ ~V ₁ C ₁+ C ₂

Correct answer

D. C ₁ ~V ₁ C ₁+ C ₂

Step-by-step solution

The charge stored by the charged condenser is Q = C ₁ ~V ₁ When the uncharged condenser is connected in parallel, the effective capacitance becomes ( C ₁+ C ₂ ) Hence the potential, V ₂= Q C ₁+ C ₂ = C ₁ ~V ₁ C ₁+ C ₂

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