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MHT CET2019Evening ShiftPhysicsCapacitanceActual

In a parallel plate air capacitor the distance between plates is reduced to one fourth and the space between them is filled with a dielectric medium of constant 2. If the initial capacity of the capacitor is 4 μ F . then its new capacity is

Options

  1. A32 μ F
  2. B18 μ F
  3. C8 μ F
  4. D44 μ F

Correct answer

A. 32 μ F

Step-by-step solution

The capacitance of a parallel plate air capacitor is given by C 0 = ε 0 A d Where, ε 0 =permittivity of the medium, A = area of plates and d = distance between the plates When the distance between plates is reduced and a dielectric slab is introduced, then the capacitance becomes C = K ε 0 A d 1 … (ii) Where, K = dielectric constant of medium. Here, K = 2, d 1 = d 4 and C 0 = 4 μ F = 4 × 10 - 6 F From Eq. (ii), we get C = 4 K ε 0 A d 1 = 4 K ε 0 A d = 4 K C 0 …. (iii) [From Eq. (i)] Substituting given values in Eq.

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