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MHT CET2011PhysicsCapacitance

If the distance between the plates of a parallel plate capacitor of capacity 10 F is doubled, then new capacity will be

Options

  1. A5 F
  2. B20 F
  3. C10 F
  4. D15 F

Correct answer

A. 5 F

Step-by-step solution

In parallel plate capacitor C= ₀ A d Now d^ =2 d Hence, C^ = ₀ A d^ = ₀ A 2 d From Eqs. (i) and (ii) array l C^ C = 1 2 C^ = C 2 array Putting C=10 F C^ = 10 2 =5 F

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