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MHT CET2010PhysicsCapacitance

Capacity of a capacitor is 48 F . When it is charged from 0.1 C to 0.5 C , change in the energy stored is

Options

  1. A2500 ~J
  2. B2.5 10⁻³ ~J
  3. C2.5 10⁶ ~J
  4. D2.42 10⁻² ~J

Correct answer

A. 2500 ~J

Step-by-step solution

Change in energy U= 1 2 [ q₁²-q₂² C ] array l = 1 2 [ (0.5)²-(0.1)² 48 10⁻⁶ ] = 1 2 [ 0.25-0.01 48 10⁻⁶ ] = 1 2 [ 0.24 48 10⁻⁶ ] = 1 2 [ 10⁴ 2 ] =2500 ~J array

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