The currents in different parts of the electric circuit are shown in following figure. The value of current i is

Step-by-step solution

Applying Kirchhoff's Current Law (KCL) at the first junction: Incoming currents are 2 A and 3 A . Current leaving the first junction = 2 A + 3 A = 5 A . Applying KCL at the second junction: Incoming current is 5 A . One outgoing branch has 1 A . Current leaving towards the third junction = 5 A - 1 A = 4 A . Applying KCL at the third junction: Incoming current is 4 A . Outgoing currents are 0.6 A , 1.3 A , and i . Therefore, 4 A = 0.6 A + 1.3 A + i 4 = 1.9 + i i = 4 - 1.9 = 2.1 A . Answer: 2.1 A