In meter bridge experiment, two resistances X and Y in the two gaps give a null point dividing the wire in the ratio 2 : 3 . When each resistance is increased by 30 , , the null point divides the wire in the ratio 5 : 6 . The resistance X and Y are respectively

Step-by-step solution

For a meter bridge, the ratio of resistances in the two gaps is equal to the ratio of the balancing lengths. Initially, the null point divides the wire in the ratio 2 : 3 . X Y = 2 3 Y = 3 2 X When each resistance is increased by 30 , , the new ratio becomes 5 : 6 . X + 30 Y + 30 = 5 6 6X + 180 = 5Y + 150 Substituting Y = 3 2 X into the equation: 6X + 180 = 5 ( 3 2 X ) + 150 6X - 15 2 X = 150 - 180 - 3 2 X = -30 X = 20 , Substituting the value of X to find Y : Y = 3 2 (20) = 30 , Answer: 20 , , 30 ,