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MHT CET202617 April 2026Evening ShiftPhysicsCurrent ElectricityActual

The current passing through the galvanometer is 4 % of the total current in the curcuit. If the resistance of the galvanometer is 'G', the shunt resistance 'S' connected across the galvanometer is

Options

  1. A25 ,G
  2. B24 ,G
  3. CG 24
  4. DG 25

Correct answer

C. G 24

Step-by-step solution

Let the total current in the circuit be I . The current passing through the galvanometer is I_g = 4 % of I = 4 100 I = I 25 . Since the galvanometer and the shunt resistance are connected in parallel, the potential difference across them is the same. I_g G = (I - I_g) S Substituting the value of I_g : ( I 25 ) G = (I - I 25 ) S I 25 G = 24I 25 S G = 24 S S = G 24 Answer: G 24

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