In the following figure, the current I is equal to

Step-by-step solution

Let the three junctions from left to right be J₁ , J₂ , and J₃ . Applying Kirchhoff's Current Law (KCL) at junction J₁ : 4.5 + 1.7 = 2.3 + I₁ (where I₁ is the current flowing from J₁ to J₂ ) I₁ = 6.2 - 2.3 = 3.9 A Applying KCL at junction J₂ : I₁ + 3.2 + 4.9 = 2.6 + I₂ (where I₂ is the current flowing from J₂ to J₃ ) 3.9 + 3.2 + 4.9 = 2.6 + I₂ 12.0 = 2.6 + I₂ I₂ = 9.4 A Applying KCL at junction J₃ : I₂ = 1.9 + I 9.4 = 1.9 + I I = 7.5 A Alternatively, considering the entire circuit as a single node, the total incomi