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MHT CET202616 April 2026Evening ShiftPhysicsCurrent ElectricityActual

A galvanometer has resistance G and range Vg. How much resistance is required to read voltage up to V volt?

Options

  1. AGV_g
  2. BG ( V - V_g V )
  3. CG ( V V_g - 1 )
  4. DG ( V + V_g V )

Correct answer

C. G ( V V_g - 1 )

Step-by-step solution

The current for full-scale deflection of the galvanometer is I_g = V_g G . To convert the galvanometer into a voltmeter of range V , a high resistance R is connected in series with it. The total resistance of the circuit becomes G + R . The new voltage range is given by V = I_g(G + R) . Substituting I_g = V_g G into the equation: V = V_g G (G + R) V V_g = G + R G V V_g = 1 + R G R G = V V_g - 1 R = G ( V V_g - 1 ) Answer: G ( V V_g - 1 )

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