MHT CET202615 April 2026Morning ShiftPhysicsCurrent ElectricityActual
If a galvanometer is shunted by ( 1 n-1 )^ th of the value of its resistance, then the fraction of the total current passing through the galvanometer is
Options
- A1 (n-1)
- B1 n
- Cn (n-1)
- D1 1-n
Correct answer
B. 1 n
Step-by-step solution
Let the resistance of the galvanometer be G and the total current in the circuit be I . The shunt resistance is given as S = G n-1 . Since the galvanometer and the shunt are connected in parallel, the potential difference across them is equal: I_g G = (I - I_g) S Substituting the value of S : I_g G = (I - I_g) G n-1 I_g (n-1) = I - I_g n I_g - I_g + I_g = I n I_g = I I_g I = 1 n The fraction of the total current passing through the galvanometer is 1 n . Answer: 1 n