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MHT CET202615 April 2026Morning ShiftPhysicsCurrent ElectricityActual

When a resistance of 200 , is connected in series with a galvanometer of resistance G, its range is V. To triple its range, a resistance of 2000 , is connected in series. The value of G is

Options

  1. A400 ,
  2. B500 ,
  3. C700 ,
  4. D900 ,

Correct answer

C. 700 ,

Step-by-step solution

Let I_g be the current for full scale deflection of the galvanometer. When a resistance of 200 , is connected in series, the range is V . V = I_g(G + 200) When a resistance of 2000 , is connected in series, the range becomes 3V . 3V = I_g(G + 2000) Dividing the second equation by the first equation: 3V V = I_g(G + 2000) I_g(G + 200) 3 = G + 2000 G + 200 3G + 600 = G + 2000 2G = 1400 G = 700 , Answer: 700 ,

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