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MHT CET202613 April 2026Evening ShiftPhysicsCurrent ElectricityActual

Resistances are joint as shown in the figure. In the balanced condition, the current I drawn from the battery is

Options

  1. A0.1 A
  2. B0.15 A
  3. C0.2 A
  4. D0.25 A

Correct answer

C. 0.2 A

Step-by-step solution

The given circuit is a Wheatstone bridge. In the balanced condition, the ratio of resistances in the adjacent arms is equal: R_ AB R_ BC = 10 10 = 1 R_ AD R_ DC = 30 30 = 1 Since R_ AB R_ BC = R_ AD R_ DC , the bridge is balanced and no current flows through the galvanometer arm BD. The circuit can be simplified as two parallel branches. Resistance of the upper branch (ABC) is R₁ = 10 + 10 = 20 . Resistance of the lower branch (ADC) is R₂ = 30 + 30 = 60 . The equivalent resistance R_ eq of the circuit is given by:

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