In the following network, the current flowing through 15 resistance is

Step-by-step solution

The given circuit is a Wheatstone bridge. Checking the balance condition: R_ AB R_ BC = 15 3 = 5 R_ AD R_ DC = 20 4 = 5 Since R_ AB R_ BC = R_ AD R_ DC , the bridge is balanced and no current flows through the 6 resistor in branch BD. The circuit simplifies to two parallel branches: Resistance of the upper branch, R₁ = 15 + 3 = 18 Resistance of the lower branch, R₂ = 20 + 4 = 24 The total current is I = 2.1 A . Using the current divider rule, the current through the 15 resistance (upper branch) is: I_ 15 = I R₂ R₁