The value of the shunt resistance that allows 10 % of the main current through the galvanometer of 99 is

Step-by-step solution

The galvanometer with resistance G = 99 , carries I_g = 0.10 I of the main current I . The shunt resistance S carries the remaining current I_s = 0.90 I . Since the galvanometer and shunt are in parallel, the voltage across both must be equal: I_g G = I_s S Substituting the current expressions: (0.10 I) G = (0.90 I) S Canceling I and solving for S : S = 0.10 0.90 G = 1 9 99 = 11 , The shunt resistance required is 11 , , corresponding to option B.