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MHT CET202519 Apr 2025Morning ShiftPhysicsCurrent ElectricityActual

If only 5 % of the total current is to be passed through galvanometer of resistance G, then the resistance of the shunt will be

Options

  1. AG 15
  2. BG 17
  3. CG 19
  4. DG 21

Correct answer

C. G 19

Step-by-step solution

A galvanometer with internal resistance G is converted into an ammeter by connecting a shunt resistance S in parallel, allowing a total current I to flow, of which only I_g = 0.05I passes through the galvanometer. The remaining current through the shunt is I_s = I - I_g = 0.95I . Since the galvanometer and shunt are in parallel, the voltage across them is equal: I_g G = I_s S Substituting the known current ratios: 0.05I G = 0.95I S Canceling the common factor of I : 0.05G = 0.95S Solving for S : S = 0.05G 0.95 = G

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