MHT CET20249 May 2024Evening ShiftPhysicsCurrent ElectricityActual
Potential difference between the points A and B is nearly
Options
- A10 V
- B14 V
- C18 V
- D20 V
Correct answer
C. 18 V
Step-by-step solution
The given circuit is a Wheatstone's bridge, As the resistances are in the same ratio, the bridge is balanced. Therefore, no current will flow through the galvanometer and the resistances will be in parallel combination. array ll & Voltage between A and C is V_ A C =I . R_ eff & 1 R_ eff = 1 (8+4) + 1 (10+5) R_ eff. = 15 12 27 =6.67 & V_ A C =4 6.67=26.68 ~V ...[From(i)] & I _ A C = V_ A C R_ A B +R_ B C = 26.68 8+4 =2.22 ~A & V_ A B =I_ A C R_ A B =2.22 8=17.76 ~V =18 ~V array