A potentiometer wire of length 1 m is connected in series with 495 resistance and 2 V battery. If 0.2 mV / cm is the potential gradient, then the resistance of the potentiometer wire is

Step-by-step solution

I= V R = 2 R+495 Potential gradient given as, array ll & = V L = I R ~L = 2 R ( R +495) .( L =1 ~m ) & 0.02= 2 R ( R +495) ( given =0.2 mV / cm ) & 0.02 ( R +495)=2 R & 1.98 R =9.9 & R = 9.9 1.98 =5 array