Only 4 % of the total current in the circuit passed through a galvanometer. If the resistance of the galvanometer is G , then the shunt resistance connected to the galvanometer is

Step-by-step solution

Relationship between the shunt resistance and galvanometer resistance is S = I ₀ G I - I _ G ....(i) I _ g = 4 100 I =0.04 I I I _ g =25 ....(ii) Putting (ii) into (i) S = G I I _ g -1 = G 25-1 = G 24