MHT CET202313 May 2023Evening ShiftPhysicsCurrent ElectricityActual
A 10 ~m long wire of resistance 20 is connected in series with a battery of e.m.f. 3 ~V (negligible internal resistance) and a resistance of 10 . The potential gradient along the wire is
Options
- A3 ~V / m
- B0.1 ~V / m
- C0.2 ~V / m
- D0.3 ~V / m
Correct answer
C. 0.2 ~V / m
Step-by-step solution
Two resistances are in series R _ net =20 +10 =30 Current I = 3 30 =0.1 ~A Potential through the wire is V =0.1 20=2 ~V Potential gradient = V 10 = 2 10 =0.2 V m