The resistances in the left and right gap of a balanced metre bridge are 12 and 36 respectively If the resistances are interchanged the balance point shifts by

Step-by-step solution

In the first case: R=12 and S=36 In balanced condition, R S = 1 100-l or 12 36 = l 100-l or 3 l=100-l or 4 l=100 l=25 ~cm Therefore, first balance point is l₁=25 ~cm In the second case: R=36 and S=12 In balanced condition, R S = l 100-l or 36 12 = 1 100-1 or l=300-3 l or 4 l=300 l=l₂=75 ~cm Therefore, second balance point is l₂=75 ~cm The shift =l₂-l₁=(75-25) cm =50 ~cm