MHT CET202122 Sep 2021Morning ShiftPhysicsCurrent ElectricityActual
In a Wheatstone bridge, three resistance P, Q and R are connected in the three arms and the fourth arm is formed by two resistances S₁ and S₂ connected in parallel. The condition for the bridge to be balanced is
Options
- AP Q = 2 R S₁+S₂
- BP Q = R (S₁+S₂ ) 2 S₁ S₂
- CP Q = R (S₁+S₂ ) S₁ S₂
- DP Q = R (S₁ S₂ ) S₁+S₂
Correct answer
C. P Q = R (S₁+S₂ ) S₁ S₂
Step-by-step solution
For balanced Wheatstone's bridge we have P Q = R S Where S is the equivalent resistance of S₁ and S₂ in parallel S= S₁ S₂ S₁+S₂ P Q = R (S₁+S₂ ) S₁ S₂