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MHT CET202019 Oct 2020Morning ShiftPhysicsCurrent ElectricityActual

A potentiometer wire of length 100 ~cm and resistance 3 is connected in series with resistance of 8 and an accumulator of 4 volt whose internal resistance is 1 A cell of e.m.f. 'E' is balanced by 50 ~cm length of the wire. The e.m.f. of the cell is

Options

  1. A1 00 volt.
  2. B0 75 volt.
  3. C0 50 volt.
  4. D0 25 volt.

Correct answer

C. 0 50 volt.

Step-by-step solution

(C) Total resistance =3+8+1=12 current. I= E R = 4 12 = 1 3 A P.D. across the wire =I R_ = 1 3 3=1 ~V potential gradient K = V L = 1 1 =1 v / m E ^ = K ^ =1 0.5=0.5 ~V

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