MHT CET202015 Oct 2020Evening ShiftPhysicsCurrent ElectricityActual
A potentiometer is used to measure the potential difference between A and B , the null point is obtained at 0.9 ~m . Now potential difference between A and C is measured, the null point is obtained at 0 3 ~m . The ratio E ₂ E ₁ is ( E ₁> E ₂ )
Options
- A3: 1
- B3: 2
- C2: 3
- D1: 3
Correct answer
C. 2: 3
Step-by-step solution
( E_ a b E_ a c = L_ a b L_ a c = E₁ E₁-E₂ = 0.9 0.3 =3 ) (E₁=3 E₁-3 E₂ ) (2 E₁=3 E₂ ) ( E₁ E₂ = 3 2 ) ( E₂ E₁ = 2 3 )