A potentiometer wire has length L for given cell of emf E, the balancing length is L 3 from the positive end of the wire. If the length of potentiometer wire is increased by 50 % , then for the same cell, the balance point is obtained at length

Step-by-step solution

For cell of emf E balancing length = L 3 = 1 3 × L (length of wire) Increased length of wire = L + L 2 = 3 L 2 Since, the cell is the same, therefore the new balancing length = 1 3 (new increased length) = 1 3 × 3 2 L = L 2 Therefore, for the same cell the balance point will be as length L 2 from positive end.