When a resistance of 100 is connected in series with a galvanometer of resistance R , its range is V. To double its range, a resistance of 1000 is connected in series. Find R .

Step-by-step solution

When a resistance of 100 is connected in series current, i= V 100+R when a resistance of 1000 is connected in series, the its range double current, i= 2 V 1100+R From Eqs. (i) and (ii) aligned V 100+R &= 2 V 1100+R R &=900 aligned