MHT CET2009PhysicsCurrent Electricity
A 2 ~V battery, a 990 resistor and a potentiometer of 2 ~m length, all are connected in series of the resistance of potentiometer wire is 10 , then the potential gradient of the potentiometer wire is
Options
- A0.05 Vm ⁻¹
- B0.5 Vm ⁻¹
- C0.01 Vm ⁻¹
- D0.1 Vm ⁻¹
Correct answer
C. 0.01 Vm ⁻¹
Step-by-step solution
Potential gradient x= e (R+R_ h +r ) R L x= 2 (990+10) 10 2 =0.01 Vm ⁻¹