A circular disc of radius 20 cm is placed in uniform magnetic field of induction 7 22 Wb/m ^2 in such a way that its axis makes an angle of 60^ with B . The magnetic flux linked with the disc is ( 60^ = 0.5)

Step-by-step solution

Radius of the disc, r = 20 cm = 0.2 m Area of the disc, A = r^2 = 22 7 (0.2)^2 = 22 7 0.04 m ^2 Magnetic field, B = 7 22 Wb/m ^2 Angle between the axis of the disc (area vector) and the magnetic field, = 60^ Magnetic flux linked with the disc is given by = B A Substituting the values: = 7 22 ( 22 7 0.04 ) 60^ = 0.04 0.5 = 0.02 Wb Answer: 0.02 Wb