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MHT CET202619 April 2026Evening ShiftPhysicsElectromagnetic InductionActual

The magnetic energy stored in an inductor of inductance 4 , H carrying a current of 1.5 A is

Options

  1. A4.5 mJ
  2. B3 , J
  3. C45 , J
  4. D4500 mJ

Correct answer

D. 4500 mJ

Step-by-step solution

The magnetic energy stored in an inductor is given by the formula: U = 1 2 LI^2 Substituting the given values, L = 4 H and I = 1.5 A: U = 1 2 4 (1.5)^2 U = 2 2.25 U = 4.5 J Converting to millijoules: U = 4.5 1000 mJ = 4500 mJ Answer: 4500 mJ

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