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MHT CET202619 April 2026Morning ShiftPhysicsElectromagnetic InductionActual

Consider two coils in which a current in one coil carrying 6 A causes the change in the flux in the second coil 12 10⁻⁴ weber/turn. The second coil has 2000 turns. The mutual inductance between the coils is

Options

  1. A0.2 H
  2. B0.3 H
  3. C0.4 H
  4. D2.4 H

Correct answer

C. 0.4 H

Step-by-step solution

The total flux linkage in the second coil is given by ₂ = N₂ ₂ . Given N₂ = 2000 and ₂ = 12 10⁻⁴ Wb/turn. ₂ = 2000 12 10⁻⁴ = 2.4 Wb. The mutual inductance M is defined by the relation ₂ = M I₁ . Given I₁ = 6 A. M = ₂ I₁ = 2.4 6 = 0.4 H. Answer: 0.4 H

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