Two coils have a mutual inductance of 0.005 H . The current changes in the first coil according to equation I = I₀ t , where I₀ = 10 A and = 60 rad s ⁻¹ . The maximum values of e.m.f. in the second coil in volt will be

Step-by-step solution

The induced e.m.f. in the second coil is given by e = -M dI dt . Given I = I₀ t , differentiating with respect to time gives dI dt = I₀ t . Thus, the induced e.m.f. is e = -MI₀ t . The maximum value of e.m.f. is e_ max = MI₀ . Substituting the given values M = 0.005 H , I₀ = 10 A , and = 60 rad s ⁻¹ : e_ max = 0.005 10 60 = 3 V . Answer: 3