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MHT CET202617 April 2026Evening ShiftPhysicsElectromagnetic InductionActual

A straight line conductor of length 0.4 m is moved with a speed of 7.0 ms ⁻¹ perpendicular to magnetic field of intensity 0.8 Wb m ⁻² . The induced e.m.f. across the conductor is

Options

  1. A2 24 V
  2. B2 80 V
  3. C3 20 V
  4. D5 60 V

Correct answer

A. 2 24 V

Step-by-step solution

Given l = 0.4 m , v = 7.0 ms ⁻¹ , and B = 0.8 Wb m ⁻² . The induced e.m.f. across a straight conductor moving perpendicular to a magnetic field is given by e = B l v . Substituting the given values: e = 0.8 0.4 7.0 e = 2.24 V Answer: 2 24 V

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