A square loop of area 25 cm ^2 has a resistance of 10 . The loop is placed in uniform magnetic field of magnitude 40 T. The plane of the loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in one second will be

Step-by-step solution

Given: Area of the loop, A = 25 cm ^2 = 25 10⁻⁴ m ^2 Resistance, R = 10 Magnetic field, B = 40 T Time taken, t = 1 s The total change in magnetic flux as the loop is pulled out of the magnetic field is: = B A = 40 25 10⁻⁴ = 0.1 Wb Since the loop is pulled out uniformly, the rate of change of flux is constant. The induced emf E is: E = t = 0.1 1 = 0.1 V The electrical power dissipated as heat in the loop due to its resistance is: P = E^2 R = (0.1)^2 10 = 0.01 10 = 10⁻³ W The work done by the external agent in pullin