Two coils P and Q are kept near each other. When no current flows through coil P and current increases in coil Q at the rate 10 ~A / s , the emf in coil P is 12 mV . When coil Q carries no current and current of 1.5 A flows through coil P , the magnetic flux linked with the coil Q in mWb is

Step-by-step solution

Mutual inductance governs the interaction between the coils. From the induced emf in coil P, E_P = 12 10⁻³ , V , due to the rate of change of current in coil Q, dI_Q dt = 10 , A/s , we apply E_P = M dI_Q dt . 12 10⁻³ = M 10 M = 1.2 10⁻³ , H For a current I_P = 1.5 , A in coil P, the magnetic flux linked with coil Q is _Q = M I_P . _Q = (1.2 10⁻³) 1.5 = 1.8 10⁻³ , Wb Converting to milliwebers, 1.8 10⁻³ , Wb = 1.8 , mWb . Final answer: 1.8