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MHT CET202525 Apr 2025Evening ShiftPhysicsElectromagnetic InductionActual

A coil of wire of radius ' r ' has 600 turns and a self-inductance of 108 mH . The self-inductance of a coil with same radius and 500 turns is

Options

  1. A80 mH
  2. B75 mH
  3. C108 mH
  4. D90 MH

Correct answer

B. 75 mH

Step-by-step solution

The self-inductance L of a coil is proportional to the square of its number of turns: L N^2 . Given initial values L₁ = 108 mH and N₁ = 600 , and final turns N₂ = 500 , the inductance becomes: L₂ = L₁ ( N₂ N₁ )^2 = 108 ( 500 600 )^2 = 108 ( 5 6 )^2 = 108 25 36 L₂ = 3 25 = 75 mH Final answer: 75 mH

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