When a current in the conducting coil is changed from 5 A in one direction to 5 A in opposite direction in 0.5 second, an average induced e.m.f in the coil is 2 V . The self-inductance of the coil is

Step-by-step solution

The induced eMF in a coil due to self-inductance follows E = -L dI dt , where L represents the self-inductance and dI dt the rate of current change. Given the initial current I₁ = 5 A and final current I₂ = -5 A, the current change is I = -10 A over t = 0.5 s, with an average induced eMF magnitude of 2 V. The magnitude equation simplifies to E_ avg = L | I t | . Substituting values gives 2 = L | -10 0.5 | = L 20 , leading to L = 2 20 = 0.1 H. Converting to millihenrys yields L = 0.1 1000 = 100 mH. The self-inductan