A copper ring is held horizontally and a bar magnet is dropped through the ring with its length along the axis of the ring. The acceleration of the falling magnet while it is passing through the ring is

Step-by-step solution

The falling magnet induces a current in the copper ring due to changing magnetic flux. According to Lenz's Law, the induced current always opposes the motion causing it, creating an upward electromagnetic force that counteracts gravity. This results in a net downward force F_ net = mg - F_ em , where F_ em > 0 . Since acceleration a = F_ net /m , we have a The magnet therefore falls with acceleration less than g .