Two coils P and Q are kept near each other. When no current flows through coil P and current increases in coil Q at the rate of 10 ~A / s , the e.m.f. in coil P is 15 mV. When coil Q carries no current and current of 1.8 A flows through coil P, the magnetic flux linked with coil Q is

Step-by-step solution

The mutual inductance M is determined from the induced emf in coil P due to the changing current in coil Q. Given E_P = 15 10⁻³ , V and dI_Q dt = 10 , A / s , the relationship E_P = M dI_Q dt yields M = 15 10⁻³ 10 = 1.5 10⁻³ , H . The magnetic flux _Q linked with coil Q when a current I_P = 1.8 , A flows through coil P is _Q = M I_P = (1.5 10⁻³) 1.8 = 2.7 10⁻³ , Wb , or 2.7 , mWb . Final answer: 2.7 , mWb