Three inductances are connected as shown in the figure. The equivalent inductance between A and B is

Step-by-step solution

Equivalent inductance between points A and B The circuit contains two 0.7 H inductors in parallel, which are then in series with a 0.85 H inductor. For parallel inductors, the equivalent is L_p = L₁ L₂ L₁ + L₂ = 0.7 0.7 0.7 + 0.7 = 0.49 1.4 = 0.35 H. The total inductance is then L_ eq = L_p + L₃ = 0.35 + 0.85 = 1.20 H. This matches option B of 1.20 H.