MHT CET20249 May 2024Evening ShiftPhysicsElectromagnetic InductionActual
A square loop ABCD is moving with constant velocity ' v ' in a uniform magnetic field ' B ' which is perpendicular to the plane of paper and directed outward. The resistance of coil is ' R ', then the rate of production of heat energy in the loop is [ L - length of side of loop]
Options
- AB^2 L^2 V R
- BB^2 L^2 V^2 R
- CB^2 LV ^2 R
- DBLV ^2 R
Correct answer
B. B^2 L^2 V^2 R
Step-by-step solution
From motional e.m.f., aligned & e _ = BLV & Heat produced = e _ R = B ^2 ~L ^2 ~V ^2 R aligned