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MHT CET20244 May 2024Evening ShiftPhysicsElectromagnetic InductionActual

A current of 0.5 A is passed through winding of a long solenoid having 400 turns. The magnetic flux linked with each turn is 3 10⁻³ ~Wb . The self inductance of the solenoid is

Options

  1. A2.4 H
  2. B2.0 H
  3. C1.2 H
  4. D0.6 H

Correct answer

A. 2.4 H

Step-by-step solution

Self inductance, L= N i L = 400 3 10⁻³ 0.5 = 1200 10⁻³ 0.5 =2.4 H

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