MHT CET20239 May 2023Morning ShiftPhysicsElectromagnetic InductionActual
An electron (mass m ) is accelerated through a potential difference of ' V ' and then it enters in a magnetic field of induction ' B ' normal to the lines. The radius of the circular path is (e = electronic charge )
Options
- A2 eV m
- B2 Vm eB ^2
- C2 Vm eB
- D2 Vm e ^2B
Correct answer
B. 2 Vm eB ^2
Step-by-step solution
Radius of circular path in a cyclotron is given by R = mV qB Here q = e , R = mV eB ... (i) On entering the field, aligned & KE = eV = 1 2 mv ^2 V & = 2 eV m ... (ii) aligned Putting (ii) into (i), R = m 2 eV m eB = 2 Vm eB ^2